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Mechanical Reasoning Guide

Springs

A spring stretches in proportion to its load. Mechanical aptitude tests ask how far it stretches, and what two or three springs do together. Can you tell?

How far do the springs stretch?

12 N/cm6 N/cm2 N/cm72 N? cm

Nine rules are all it takes. Read on, then try the test.

Where it appears

Questions about springs and weights belong to mechanical reasoning (or mechanical comprehension) tests, beside the gears, levers and pulleys. Each shows a picture and asks what happens next. You will meet them in:

Bennett Mechanical Comprehension TestThe classic test of mechanical understanding, used in hiring for technical and engineering roles. Springs and weights are among its everyday-physics topics.
Differential Aptitude Tests (DAT)Its Mechanical Reasoning subtest, used in school and career guidance.
ASVABThe Mechanical Comprehension section of the US military's entrance test.
Technician and apprenticeship testsMechanical aptitude tests for maintenance, manufacturing and trade roles, and the mechanical sections of employers' aptitude batteries.

Those tests usually give a picture with no numbers to count and no time to spare. Here every picture carries its numbers, so each answer is exact, and the questions grow harder as you get better. It trains the habit those questions reward: find the load each spring carries, then the stiffness it has.

One spring: four rules

Every spring shows its stiffness in newtons per centimetre (N/cm): the load that stretches it 1 cm. The weight hanging from it is in newtons (N). The question is how far it stretches, what load gives a stretch, how long it is with the load on, or which of four springs stretches most.

1Stretch = load ÷ stiffness

A 5 N/cm spring needs 5 N for every centimetre, so a 30 N load stretches it six of them.

stretch = load ÷ stiffness
Divide, never multiply: a stiffer spring stretches less. And do not take the stiffness away from the load.
(not to scale)5 N/cm30 N6 cm30 N ÷ 5 N/cm = 6 cm
30 N on a 5 N/cm spring: 6 cm

2Twice the load, twice the stretch

When the stiffness is not given, a first stretch gives it: load ÷ stretch. Or keep the ratio: a load one and a half times as big stretches the same spring one and a half times as far. The same idea turns a stretch back into the load that caused it.

stiffness = load ÷ stretch
The slip is to add the extra load to the stretch. The stretch is in proportion, so a heavier load multiplies it, it does not add to it.
20 N4 cm30 N6 cmthe same spring both times (not to scale)firstthen20 N stretches it 4 cm, so 5 N per cm; 30 ÷ 5 = 6 cm
20 N stretches it 4 cm, so 5 N per cm; 30 N is 6 cm

3The length is the spring's own length plus the stretch

A spring that is 15 cm long with nothing on it is longer when loaded. Work out the stretch first, then add it to the unloaded length.

Giving the stretch alone is a slip, and so is adding the load to the length without dividing by the stiffness.
(not to scale)5 N/cm25 N20 cm15 cmunloadedstretch 25 ÷ 5 = 5 cm, so 15 + 5 = 20 cm
25 N ÷ 5 N/cm = 5 cm of stretch, so 15 + 5 = 20 cm

4Which of four stretches most?

Do not guess from the picture: work out every spring's stretch with rule 1, then pick the biggest. The same goes for which ends up longest, where each spring's own length is added in first.

Two traps in every question: the spring with the heaviest load and the softest spring. In the test neither is ever the answer. A heavy load on a stiff spring is small, and a soft spring under a light load is small too.
(not to scale)3 N/cm42 NA42 ÷ 3= 14 cm15 N/cm105 NB105 ÷ 15= 7 cm12 N/cm24 NC24 ÷ 12= 2 cm2 N/cm16 ND16 ÷ 2= 8 cmStretch = weight ÷ stiffness
14, 7, 2 and 8 cm: A stretches most, though B has the heaviest load and D the softest spring

Springs together: five rules

Springs can hang side by side, sharing a load, or one below another, each carrying it. Look at where the weight hangs and which springs it pulls on. The question is how far they stretch together.

5Side by side: the stiffnesses add

Two springs side by side share the load, so together they are a stiffer spring. Add their stiffnesses, then divide the load by the total. Identical springs side by side stretch only 1/2 (or 1/3 ...) as far as one on its own.

stiffness = k + k
Do not add their stretches: that is the rule for the other arrangement.
12 N/cm6 N/cm144 N8 cmside by side: 12 + 6 = 18 N/cm; 144 ÷ 18 = 8 cm
12 + 6 = 18 N/cm; 144 ÷ 18 = 8 cm

6One below another: the stretches add

Each spring carries the whole load, so each stretches on its own, and the two stretches add. Identical springs one below another stretch twice (or three times) as far as one.

stretch = load ÷ k + load ÷ k
Do not add the stiffnesses or average the stretches. Here 2 + 5 = 7 N/cm would give far too little.
2 N/cm5 N/cm40 N28 cmone below another: 40 ÷ 2 + 40 ÷ 5 = 20 + 8 = 28 cm
40 N on each: 40 ÷ 2 = 20 cm and 40 ÷ 5 = 8 cm; together 28 cm

7A chain: each spring carries what hangs below it

With a weight at every joint, the top spring carries all the weights under it, and the lower spring only the one beneath it. Work out each spring's own load first, then each stretch, then add.

Giving the top spring only the weight just under it is the slip, and so is giving both springs only the lower weight.
5 N/cm15 N5 N/cm20 N7 cm4 cmtop springlower springTop spring carries 15 + 20 = 35 N: 35 ÷ 5 = 7 cmLower spring carries 20 N: 20 ÷ 5 = 4 cm; 7 + 4 = 11 cm
Top spring carries 15 + 20 = 35 N: 7 cm. Lower carries 20 N: 4 cm. Together 11 cm

8A network: work from the inside out

A network mixes the two arrangements: a pair of springs and a third. Turn the pair into one spring first. Side by side, its stiffness is the two added (rule 5); one below another, their stretches add (rule 6), so its stiffness is 1 ÷ (1 ÷ k + 1 ÷ k). Then join that one spring to the third as the picture shows. A question may also ask which of four arrangements stretches least: work out each one's stretch the same way.

Taking every spring as one below another, or every spring as side by side, or swapping the two arrangements, are the slips.
12 N/cm6 N/cm8 N/cm144 N26 cmThe pair side by side: 12 + 6 = 18 N/cmOne below another: 144 ÷ 18 + 144 ÷ 8 = 8 + 18 = 26 cm
The pair: 12 + 6 = 18 N/cm, so 144 ÷ 18 = 8 cm; the third: 144 ÷ 8 = 18 cm; together 26 cm

9A beam on two springs: the nearer spring carries more

A light beam hangs from two springs, with a weight placed along it. The weight is shared like a lever's: each spring carries the weight times the distance from the weight to the other spring, over the length of the beam. Then each spring stretches by its own share divided by its own stiffness.

Sharing the weight equally when it hangs off centre is the slip, and so is giving a spring the other one's share.
5 N/cmA10 N/cmB1234590 N(the beam is light; places counted from the left end; not to scale)A carries 90 × 2 ÷ 6 = 30 N, B carries 90 × 4 ÷ 6 = 60 NSpring A: 30 ÷ 5 = 6 cm
A carries 90 × 2 ÷ 6 = 30 N and B carries 60 N; spring A: 30 ÷ 5 = 6 cm

Two questions, solved

1A question about one spring each

Which spring stretches the most?

(not to scale)6 N/cm78 NA2 N/cm4 NB10 N/cm90 NC3 N/cm12 ND
The question

Try it first, then open the answer.

Show the answer: spring A
  1. Work out every spring's stretch: the weight over the stiffness.
  2. A: 78 ÷ 6 = 13 cm.
  3. B: 4 ÷ 2 = 2 cm.
  4. C: 90 ÷ 10 = 9 cm.
  5. D: 12 ÷ 3 = 4 cm.
  6. A stretches most, 13 cm. The traps: C has the heaviest weight and B the softest spring, but neither stretches most.

The other options, and the slip each one is:

B The softest spring, but a lighter load (2 cm)C The heaviest load, but a stiffer spring (9 cm)D Stretches less (4 cm)
(not to scale)6 N/cm78 NA78 ÷ 6= 13 cm2 N/cm4 NB4 ÷ 2= 2 cm10 N/cm90 NC90 ÷ 10= 9 cm3 N/cm12 ND12 ÷ 3= 4 cmStretch = weight ÷ stiffness
The working, on the picture

2A question about springs together

How far do the springs stretch?

2 N/cm6 N/cm4 N/cm96 N? cm
The question

Try it first, then open the answer.

Show the answer: 36 cm
  1. The pair side by side: 2 + 6 = 8 N/cm
  2. One below another: 96 ÷ 8 + 96 ÷ 4 = 12 + 24 = 36 cm

The other options, and the slip each one is:

8 cm Every spring taken as side by side72 cm Not what Hooke's law gives88 cm Every spring taken as one below another
2 N/cm6 N/cm4 N/cm96 N36 cmThe pair side by side: 2 + 6 = 8 N/cmOne below another: 96 ÷ 8 + 96 ÷ 4 = 12 + 24 = 36 cm
The working, on the picture

How the practice test runs

Try the Springs test

Free and adaptive, no account needed. Start with one spring and climb to chains, networks and a beam on two springs.

Start the Springs test